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| Test 1 | |
| Name: Lucky picker | Time: approximately 20min |
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Now, make a program which will ask the user to enter a number. Then it will say if you picked the lucky number (a number you come up with), it will repeat this process until the user gueses the lucky number. If the user types in a number larger than the lucky number, it will say "Lower" , if the user picks a smaller number, it will say "Larger", if the user picks the lucky number, then the program outputs a congratulations, and waits for the user to press a key , then the program will exit. Also you may make the lucky number a random number (shown in lesson 2). |
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| Test 2 | |
| Name: Loopy | Time: 10 min |
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Get the user to input there name, then ask them for their age. Now output their name on to
the screen in a single line as many times as there age is. | |
| Test 3 | |
| Name: Blackout | Time: 10 min |
| Full up the screen with any letter or number, try to get the exact amount. Hint: the screen is 80 characters across by 25 down. | |
| Answers | ||
| Drag the cursor over the white space to highlight the answer | ||
| Test 1 | Lucky picker | Program , Source code |
#include <conio.h>
#include <iostream.h>
#include <time.h>
void main()
{
int Number, R_number;
randomize();
R_number = rand()%100;
cout << " Lucky Picker" << endl << endl;
cout << "Please enter a number between 0 and 100: ";
cin >> Number;
while(Number!=R_number)
{
if(Number > R_number)
{
cout << "Smaller" << endl;
}
else if(Number < R_number)
{
cout << "Larger" << endl;
}
cout << "Please enter a number between 0 and 100: ";
cin >> Number;
}
cout << "Congratulations. You picked the lucky number: " << R_number;
getch();
}
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| Test 2 | Loopy | Program , Source code |
#include <conio.h>
#include <iostream.h>
void main()
{
int Age;
char Name[20];
cout << "Please enter your first name: ";
cin >> Name;
cout << "Please enter your age: ";
cin >> Age;
while(Age>0)
{
cout << Name << endl;
Age--;
}
cout << "If this looks alot to you, then your pretty old.";
getch();
}
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| Test 3 | Blackout | Program , Source code |
#include <conio.h>
#include <iostream.h>
void main()
{
int x,y;
for(y=0;y<25;y++)
{
for(x=0;x<79;x++)
{
cout << "E";
}
cout << endl;
}
getch();
}
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